Pointers MCQs in C Language

Pointers MCQs in C Language

1.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    printf("%d", *p);
}

A) 0
B) 10
C) Address of a
D) Compiler error

✅ Answer: B
Explanation:
*p dereferences pointer → prints value of a → 10.

---

2.

Output:

#include <stdio.h>
int main() {
    int a = 20, b = 30;
    int *p = &a;
    p = &b;
    printf("%d", *p);
}

A) 20
B) 30
C) Address of b
D) Compiler error

✅ Answer: B
Explanation:
Pointer reassigned → points to b → dereference → 30.

---

3.

What is the correct way to declare a pointer to an integer?

A) int *p;
B) int &p;
C) int p*;
D) pointer p;

✅ Answer: A
Explanation:
int *p; declares a pointer to int. & is address-of operator.

---

4.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    *p = 10;
    printf("%d", a);
}

A) 5
B) 10
C) Compiler error
D) Garbage

✅ Answer: B
Explanation:
*p = 10 updates the value of a via pointer → 10.

---

5.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%p", p);
}

A) 5
B) Address of a
C) Garbage
D) Compiler error

✅ Answer: B
Explanation:
%p prints pointer → memory address of a.

---

6.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = NULL;
    p = &a;
    printf("%d", *p);
}

A) 0
B) 5
C) NULL
D) Compiler error

✅ Answer: B
Explanation:
Pointer initialized NULL, then assigned → dereference → 5.

---

7.

Output:

#include <stdio.h>
int main() {
    int a = 5, b = 10;
    int *p1 = &a, *p2 = &b;
    *p1 = *p2;
    printf("%d %d", a, b);
}

A) 5 10
B) 10 10
C) 5 5
D) Compiler error

✅ Answer: B
Explanation:
*p1 = *p2 → a = b → a = 10, b = 10.

---

8.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    printf("%d", p);
}

A) 10
B) Address of a
C) 0
D) Compiler error

✅ Answer: B
Explanation:
Printing pointer variable → memory address of a.

---

9.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", sizeof(p));
}

A) 2
B) 4
C) 8
D) Depends on system

✅ Answer: D
Explanation:
Size of pointer depends on system architecture: 32-bit → 4 bytes, 64-bit → 8 bytes.

---

10.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p;
    p = &a;
    printf("%d", *p + 5);
}

A) 5
B) 10
C) Compiler error
D) Garbage

✅ Answer: B
Explanation:
Dereference pointer → value 5 + 5 → 10.

---

11.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    int **q = &p;
    printf("%d", **q);
}

A) 5
B) Address of a
C) Compiler error
D) 0

✅ Answer: A
Explanation:
Pointer to pointer → **q points to p → *q = p → **q = a → 5.

---

12.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    int **q = &p;
    **q = 10;
    printf("%d", a);
}

A) 5
B) 10
C) Compiler error
D) Garbage

✅ Answer: B
Explanation:
**q → p → a → updating **q updates a → 10.

---

13.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {1, 2, 3};
    int *p = arr;
    printf("%d", *(p+1));
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: B
Explanation:
Pointer arithmetic → p+1 → arr[1] → 2.

---

14.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {1, 2, 3};
    int *p = arr;
    printf("%d", *p + 2);
}

A) 1
B) 3
C) 2
D) Compiler error

✅ Answer: B
Explanation:
*p = arr[0] = 1 → 1 + 2 = 3.

---

15.

Which of the following is valid pointer initialization?

A) int *p = 5;
B) int *p = NULL;
C) int *p = "10";
D) int *p = *a;

✅ Answer: B
Explanation:
Pointers can be initialized to NULL. Others are invalid.

---

16.

Output:

#include <stdio.h>
int main() {
    char ch = 'A';
    char *p = &ch;
    printf("%c", *p);
}

A) A
B) ch
C) Compiler error
D) Address

✅ Answer: A
Explanation:
Dereference pointer → value of char → ‘A’.

---

17.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    int *q = p;
    *q = 20;
    printf("%d", a);
}

A) 10
B) 20
C) Compiler error
D) Garbage

✅ Answer: B
Explanation:
*q = 20 → updates a → 20.

---

18.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    printf("%u", p);
}

A) 10
B) Address of a
C) Garbage
D) Compiler error

✅ Answer: B
Explanation:
%u prints pointer as unsigned int → memory address of a.

---

19.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%u", *p);
}

A) 5
B) Address of a
C) Compiler error
D) Garbage

✅ Answer: A
Explanation:
Dereference pointer → value of a → 5.

---

20.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p;
    p = &a;
    printf("%d", *p++);
}

A) 5
B) 6
C) Compiler error
D) Garbage

✅ Answer: A
Explanation:
p++ → prints current value (p = 5), then increments pointer → 5.

---

21.

Output:

#include <stdio.h>
int main() {
    int a = 5, b = 10;
    int *p = &a, *q = &b;
    *p = *q + *p;
    printf("%d %d", a, b);
}

A) 5 10
B) 15 10
C) 10 15
D) 15 15

✅ Answer: B
Explanation:
*p = *q + *p → 10 + 5 = 15 → a = 15, b = 10.

---

22.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    printf("%p %p", p, &a);
}

A) Same addresses
B) Different addresses
C) Compiler error
D) Garbage

✅ Answer: A
Explanation:
p stores address of a → &a → same memory address.

---

23.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    int **q = &p;
    printf("%d", *p + **q);
}

A) 5
B) 10
C) Compiler error
D) 0

✅ Answer: B
Explanation:
*p = 5, **q = 5 → 5 + 5 = 10.

---

24.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {1, 2, 3};
    int *p = arr;
    printf("%d", *(p+2));
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: C
Explanation:
Pointer arithmetic → p+2 → arr[2] → 3.

---

25.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {1, 2, 3};
    int *p = arr;
    printf("%d", *p++);
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: A
Explanation:
*p++ → prints current value → arr[0] = 1, then increments pointer.

---

26.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    printf("%d", ++*p);
}

A) 10
B) 11
C) Compiler error
D) 9

✅ Answer: B
Explanation:
++*p → increments value pointed → 10 → 11.

---

27.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    int **q = &p;
    printf("%d", **q);
}

A) 0
B) 5
C) Address of a
D) Compiler error

✅ Answer: B
Explanation:
**q → p → a → 5.

---

28.

Output:

#include <stdio.h>
int main() {
    int arr[] = {1, 2, 3};
    int *p = arr;
    printf("%d", *(p+1)+*(p+2));
}

A) 3
B) 5
C) 4
D) 6

✅ Answer: B
Explanation:
*(p+1) = 2, *(p+2) = 3 → sum = 5.

---

29.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    *p += 5;
    printf("%d", a);
}

A) 5
B) 10
C) Compiler error
D) 0

✅ Answer: B
Explanation:
*a += 5 → 10.

---

30.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%p", (void*)p);
}

A) Address of a
B) 5
C) Compiler error
D) Garbage

✅ Answer: A
Explanation:
Casting pointer to void* → prints memory address.

---

31.

Output:

#include <stdio.h>
int main() {
    int arr[] = {1, 2, 3};
    int *p = arr;
    printf("%d", *arr+2);
}

A) 1
B) 3
C) 2
D) Compiler error

✅ Answer: B
Explanation:
*arr = arr[0] = 1 → 1 + 2 = 3.

---

32.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    int **q = &p;
    **q += 5;
    printf("%d", a);
}

A) 5
B) 10
C) Compiler error
D) 0

✅ Answer: B
Explanation:
**q → p → a → a += 5 → 10.

---

33.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {1,2,3};
    int *p = arr;
    printf("%d", p[2]);
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: C
Explanation:
p[2] → arr[2] → 3.

---

34.

Output:

#include <stdio.h>
int main() {
    int arr[] = {10,20,30};
    int *p = arr;
    printf("%d", *(p+1)+1);
}

A) 21
B) 20
C) 31
D) Compiler error

✅ Answer: C
Explanation:
*(p+1) = 20 → 20+1 = 21? Wait carefully.
Yes, *(p+1)+1 = 20+1 = 21 ✅.

---

35.

Output:

#include <stdio.h>
int main() {
    int a = 5, b = 10;
    int *p = &a, *q = &b;
    *p = *q;
    printf("%d %d", a, b);
}

A) 5 10
B) 10 10
C) 5 5
D) Compiler error

✅ Answer: B
Explanation:
*p = *q → a = b → a = 10, b = 10.

---

36.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    printf("%d", *p--);
}

A) 10
B) 11
C) Compiler error
D) Garbage

✅ Answer: A
Explanation:
*p– → prints current value → 10, then decrements pointer (undefined in this context, but prints 10).

---

37.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {1,2,3};
    int *p = arr+2;
    printf("%d", *p);
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: C
Explanation:
arr+2 → arr[2] → 3.

---

38.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", ++*p);
}

A) 5
B) 6
C) Compiler error
D) 0

✅ Answer: B
Explanation:
++*p → increment value pointed → 5+1 = 6.

---

39.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    *p += 10;
    printf("%d", a);
}

A) 5
B) 15
C) Compiler error
D) 0

✅ Answer: B
Explanation:
*a += 10 → 15.

---

40.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    int **q = &p;
    printf("%d", **q + 5);
}

A) 10
B) 15
C) Compiler error
D) 5

✅ Answer: B
Explanation:
**q → p → a → 10 + 5 = 15.

---

41.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", p - &a);
}

A) 0
B) 1
C) Compiler error
D) Garbage

✅ Answer: A
Explanation:
Pointer subtraction → same address → 0.

---

42.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {1,2,3};
    int *p = arr;
    printf("%d", *(p+0));
}

A) 0
B) 1
C) 2
D) 3

✅ Answer: B
Explanation:
*(p+0) → arr[0] → 1.

---

43.

Output:

#include <stdio.h>
int main() {
    int arr[] = {10,20,30};
    int *p = arr;
    printf("%d", *(p+2));
}

A) 10
B) 20
C) 30
D) Compiler error

✅ Answer: C
Explanation:
*(p+2) → arr[2] → 30.

---

44.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%p", p++);
}

A) Address of a before increment
B) Address of a after increment
C) Compiler error
D) Garbage

✅ Answer: A
Explanation:
p++ → prints current address → then increments pointer.

---

45.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", *++p);
}

A) 5
B) Compiler error
C) Garbage
D) 0

✅ Answer: C
Explanation:
Pointer increment on a single int variable → undefined behavior → likely garbage.

---

46.

Output:

#include <stdio.h>
int main() {
    int arr[] = {1,2,3,4};
    int *p = arr;
    printf("%d", *(p+3));
}

A) 1
B) 2
C) 3
D) 4

✅ Answer: D
Explanation:
*(p+3) → arr[3] → 4.

---

47.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    int **q = &p;
    printf("%d", *p + **q);
}

A) 5
B) 10
C) Compiler error
D) 0

✅ Answer: B
Explanation:
*p = 5, **q = 5 → sum = 10.

---

48.

Output:

#include <stdio.h>
int main() {
    int arr[2] = {10,20};
    int *p = arr;
    printf("%d", *p + *(p+1));
}

A) 10
B) 20
C) 30
D) Compiler error

✅ Answer: C
Explanation:
*p = 10, *(p+1) = 20 → sum = 30.

---

49.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", *p * 2);
}

A) 5
B) 10
C) Compiler error
D) 0

✅ Answer: B
Explanation:
Dereference pointer → 5 × 2 = 10.

---

50.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    *p *= 2;
    printf("%d", a);
}

A) 5
B) 10
C) Compiler error
D) 0

✅ Answer: B
Explanation:
*a *= 2 → a = 10.

---

51.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {1,2,3};
    int *p = arr;
    printf("%d", *(p++));
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: A
Explanation:
*p++ prints current value → arr[0] = 1, then pointer increments.

---

52.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {10,20,30};
    int *p = arr;
    printf("%d", *++p);
}

A) 10
B) 20
C) 30
D) Compiler error

✅ Answer: B
Explanation:
++p → points to arr[1] → *p = 20.

---

53.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", *p--);
}

A) 5
B) 4
C) Compiler error
D) Garbage

✅ Answer: A
Explanation:
*p– prints current value → 5, then decrements pointer.

---

54.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", --*p);
}

A) 5
B) 4
C) Compiler error
D) 6

✅ Answer: B
Explanation:
–*p decrements value pointed → a = 4.

---

55.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", *p + 3);
}

A) 5
B) 8
C) Compiler error
D) 3

✅ Answer: B
Explanation:
*a = 5 → 5 + 3 = 8.

---

56.

Output:

#include <stdio.h>
int main() {
    int arr[] = {1,2,3,4};
    int *p = arr;
    int *q = p + 2;
    printf("%d", *q);
}

A) 1
B) 2
C) 3
D) 4

✅ Answer: C
Explanation:
p + 2 → arr[2] → 3.

---

57.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {10,20,30};
    int *p = arr;
    printf("%d", *(arr+1));
}

A) 10
B) 20
C) 30
D) Compiler error

✅ Answer: B
Explanation:
*(arr+1) → arr[1] → 20.

---

58.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    int **q = &p;
    **q += 2;
    printf("%d", a);
}

A) 5
B) 7
C) Compiler error
D) 2

✅ Answer: B
Explanation:
**q → p → a → a += 2 → 7.

---

59.

Output:

#include <stdio.h>
int main() {
    int arr[] = {1,2,3};
    int *p = arr;
    printf("%d", *p + *(p+1) + *(p+2));
}

A) 3
B) 6
C) 5
D) Compiler error

✅ Answer: B
Explanation:
Sum → 1+2+3 = 6.

---

60.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    printf("%d", *p);
}

A) 10
B) Address of a
C) Compiler error
D) 0

✅ Answer: A
Explanation:
Dereferencing pointer → value → 10.

---

61.

Output:

#include <stdio.h>
int main() {
    int arr[] = {1,2,3};
    int *p = arr;
    printf("%d", p[1]);
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: B
Explanation:
p[1] → arr[1] → 2.

---

62.

Output:

#include <stdio.h>
int main() {
    int arr[] = {10,20,30};
    int *p = arr;
    printf("%d", *(p+0));
}

A) 0
B) 10
C) 20
D) Compiler error

✅ Answer: B
Explanation:
*(p+0) → arr[0] → 10.

---

63.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    int **q = &p;
    printf("%d", **q * 2);
}

A) 5
B) 10
C) Compiler error
D) 0

✅ Answer: B
Explanation:
*q → p → a → 52 = 10.

---

64.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    *p -= 5;
    printf("%d", a);
}

A) 10
B) 5
C) Compiler error
D) 0

✅ Answer: B
Explanation:
*a -= 5 → a = 5.

---

65.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", *p--);
}

A) 5
B) 4
C) Compiler error
D) Garbage

✅ Answer: A
Explanation:
*p– prints current value → 5, then decrements pointer.

---

66.

Output:

#include <stdio.h>
int main() {
    int arr[] = {1,2,3,4};
    int *p = arr+3;
    printf("%d", *(p-2));
}

A) 1
B) 2
C) 3
D) 4

✅ Answer: B
Explanation:
p → arr+3 → arr[3] → *(p-2) = arr[1] = 2.

---

67.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    int **q = &p;
    printf("%d", **q - 2);
}

A) 3
B) 5
C) Compiler error
D) 2

✅ Answer: A
Explanation:
**q → p → a → 5-2 = 3.

---

68.

Output:

#include <stdio.h>
int main() {
    int arr[2] = {10,20};
    int *p = arr;
    printf("%d", *(p+1) - *p);
}

A) 10
B) 20
C) Compiler error
D) 30

✅ Answer: A
Explanation:
*(p+1) = 20, *p = 10 → 20-10 = 10.

---

69.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", (*p)++);
}

A) 5
B) 6
C) Compiler error
D) 0

✅ Answer: A
Explanation:
Post-increment → prints 5, then a = 6.

---

70.

Output:

#include <stdio.h>
int main() {
    int arr[] = {1,2,3};
    int *p = arr;
    printf("%d", *(p++) + *p);
}

A) 3
B) 4
C) 5
D) Compiler error

✅ Answer: C
Explanation:
*(p++) = arr[0] =1, *p after increment → arr[1]=2 → sum=3? Wait carefully.
*(p++) = 1 → p increments → now p → arr[1] → *p = 2 → 1+2=3 ✅.
Answer: 3.

---

71.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    int **q = &p;
    *p += 5;
    printf("%d", **q);
}

A) 10
B) 15
C) Compiler error
D) 5

✅ Answer: B
Explanation:
*p +=5 → a=15 → **q dereference = 15.

---

72.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {1,2,3};
    int *p = arr;
    p += 2;
    printf("%d", *p);
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: C
Explanation:
Pointer arithmetic → arr+2 → arr[2] → 3.

---

73.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    int **q = &p;
    printf("%d", *p + **q);
}

A) 5
B) 10
C) Compiler error
D) 0

✅ Answer: B
Explanation:
*p=5, **q=5 → sum=10.

---

74.

Output:

#include <stdio.h>
int main() {
    int arr[] = {1,2,3,4};
    int *p = arr;
    printf("%d", *(p+3));
}

A) 1
B) 2
C) 3
D) 4

✅ Answer: D
Explanation:
*(p+3) → arr[3] = 4.

---

75.

Output:

#include <stdio.h>
int main() {
    int a = 10;
    int *p = &a;
    int **q = &p;
    **q -= 5;
    printf("%d", a);
}

A) 10
B) 5
C) Compiler error
D) 0

✅ Answer: B
Explanation:
**q → p → a → a -=5 → 5.

---

76.

Output:

#include <stdio.h>
int main() {
    int arr[] = {5,10,15};
    int *p = arr;
    printf("%d", *(p++) + *(p++));
}

A) 5
B) 15
C) 20
D) Compiler error

✅ Answer: C
Explanation:
*(p++)=5, p → arr[1], *(p++)=10 → sum = 15? Wait carefully.
*(p++)=5, p increments → now p→ arr[1], *(p++)=10 → sum=5+10=15 ✅.

---

77.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", (*p)++);
}

A) 5
B) 6
C) Compiler error
D) 0

✅ Answer: A
Explanation:
Post-increment prints 5 → a becomes 6.

---

78.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", ++*p);
}

A) 5
B) 6
C) Compiler error
D) 0

✅ Answer: B
Explanation:
Pre-increment → increments value before printing → 6.

---

79.

Output:

#include <stdio.h>
int main() {
    int arr[3] = {1,2,3};
    int *p = arr;
    printf("%d", *(p+1) * 2);
}

A) 2
B) 4
C) 6
D) Compiler error

✅ Answer: B
Explanation:
(p+1) = 2 → 22=4.

---

80.

Output:

#include <stdio.h>
int main() {
    int a = 5;
    int *p = &a;
    printf("%d", *p + 10);
}

A) 5
B) 10
C) 15
D) Compiler error

✅ Answer: C
Explanation:
*a = 5 → 5+10=15.

---

81.

Output:

#include <stdio.h>
int main() {
    int arr[] = {1,2,3};
    int *p = arr;
    printf("%d", *(p++) + *(++p));
}

A) 3
B) 4
C) 5
D) Compiler error

✅ Answer: C
Explanation:
*(p++)=1, ++p → p points arr[2] → *p=3 → sum =1+3=4? Wait carefully.
p starts at arr[0], *(p++)=1 → p→ arr[1], ++p → p→ arr[2], *p=3 → sum=1+3=4 ✅.

Answer: 4

---

82.

Output:

#include <stdio.h>
int main() {
    int a=5;
    int *p=&a;
    printf("%d", *p * *p);
}

A) 5
B) 10
C) 25
D) Compiler error

✅ Answer: C
Explanation:
5*5=25.

---

83.

Output:

#include <stdio.h>
int main() {
    int arr[2]={10,20};
    int *p=arr;
    printf("%d", *(p+1) / *p);
}

A) 2
B) 0
C) 1
D) Compiler error

✅ Answer: A
Explanation:
20/10=2.

---

84.

Output:

#include <stdio.h>
int main() {
    int a=10;
    int *p=&a;
    int **q=&p;
    printf("%d", **q);
}

A) 10
B) Address of a
C) Compiler error
D) 0

✅ Answer: A
Explanation:
**q → p → a → 10.

---

85.

Output:

#include <stdio.h>
int main() {
    int arr[]={1,2,3,4};
    int *p=arr;
    printf("%d", *(p+3)-*(p));
}

A) 3
B) 4
C) 5
D) Compiler error

✅ Answer: A
Explanation:
*(p+3)=4, *p=1 →

4-1=3.

---

86.

Output:

#include <stdio.h>
int main() {
    int arr[]={1,2,3};
    int *p=arr;
    printf("%d", *(++p));
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: B
Explanation:
++p → points arr[1] → *p=2.

---

87.

Output:

#include <stdio.h>
int main() {
    int arr[]={1,2,3};
    int *p=arr+2;
    printf("%d", *(p--));
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: C
Explanation:
*(p–) prints arr[2]=3, then pointer decrements.

---

88.

Output:

#include <stdio.h>
int main() {
    int a=5;
    int *p=&a;
    printf("%d", (*p)++);
}

A) 5
B) 6
C) Compiler error
D) 0

✅ Answer: A
Explanation:
Post-increment → prints 5 → a=6.

---

89.

Output:

#include <stdio.h>
int main() {
    int a=5;
    int *p=&a;
    printf("%d", ++(*p));
}

A) 5
B) 6
C) Compiler error
D) 0

✅ Answer: B
Explanation:
Pre-increment → a=6, prints 6.

---

90.

Output:

#include <stdio.h>
int main() {
    int arr[]={1,2,3,4};
    int *p=arr;
    printf("%d", *(p+1)+*(p+2));
}

A) 3
B) 5
C) 6
D) Compiler error

✅ Answer: B
Explanation:
*(p+1)=2, *(p+2)=3 → sum=5.

---

91.

Output:

#include <stdio.h>
int main() {
    int a=5;
    int *p=&a;
    int **q=&p;
    printf("%d", **q+2);
}

A) 5
B) 7
C) Compiler error
D) 2

✅ Answer: B
Explanation:
**q → p → a → 5+2=7.

---

92.

Output:

#include <stdio.h>
int main() {
    int arr[]={2,4,6};
    int *p=arr;
    printf("%d", *(p+2)/*(p));
}

A) 2
B) 3
C) 6
D) Compiler error

✅ Answer: B
Explanation:
*(p+2)=6, *p=2 → 6/2=3.

---

93.

Output:

#include <stdio.h>
int main() {
    int a=10;
    int *p=&a;
    printf("%d", *p*2);
}

A) 10
B) 20
C) Compiler error
D) 0

✅ Answer: B
Explanation:
10*2=20.

---

94.

Output:

#include <stdio.h>
int main() {
    int arr[]={1,2,3};
    int *p=arr;
    printf("%d", *(p+0)+*(p+2));
}

A) 1
B) 3
C) 4
D) 5

✅ Answer: D
Explanation:
*(p+0)=1, *(p+2)=3 → sum=4 → Wait carefully. Sum=1+3=4 ✅

Answer: 4

---

95.

Output:

#include <stdio.h>
int main() {
    int a=5;
    int *p=&a;
    *p += 10;
    printf("%d", a);
}

A) 5
B) 10
C) 15
D) Compiler error

✅ Answer: C
Explanation:
*a += 10 → 5+10=15.

---

96.

Output:

#include <stdio.h>
int main() {
    int arr[]={1,2,3};
    int *p=arr;
    printf("%d", *p + *(p+1) + *(p+2));
}

A) 5
B) 6
C) 7
D) Compiler error

✅ Answer: B
Explanation:
1+2+3=6.

---

97.

Output:

#include <stdio.h>
int main() {
    int a=5;
    int *p=&a;
    int **q=&p;
    printf("%d", **q);
}

A) 0
B) 5
C) Compiler error
D) Address of a

✅ Answer: B
Explanation:
**q → p → a → 5.

---

98.

Output:

#include <stdio.h>
int main() {
    int arr[]={1,2,3,4};
    int *p=arr;
    printf("%d", *(p+3)-*(p+1));
}

A) 2
B) 3
C) 1
D) Compiler error

✅ Answer: A
Explanation:
*(p+3)=4, *(p+1)=2 → 4-2=2.

---

99.

Output:

#include <stdio.h>
int main() {
    int arr[]={10,20,30};
    int *p=arr;
    printf("%d", *(p+1)/ *(p));
}

A) 1
B) 2
C) 3
D) Compiler error

✅ Answer: B
Explanation:
20/10=2.

---

100.

Output:

#include <stdio.h>
int main() {
    int a=5;
    int *p=&a;
    printf("%d", *p + *p);
}

A) 5
B) 10
C) Compiler error
D) 0

✅ Answer: B
Explanation:
*a=5 → 5+5=10.

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