Pointers MCQs in C Language
1.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
printf("%d", *p);
}A) 0
B) 10
C) Address of a
D) Compiler error
✅ Answer: B
Explanation:*p dereferences pointer → prints value of a → 10.
2.
Output:
#include <stdio.h>
int main() {
int a = 20, b = 30;
int *p = &a;
p = &b;
printf("%d", *p);
}A) 20
B) 30
C) Address of b
D) Compiler error
✅ Answer: B
Explanation:
Pointer reassigned → points to b → dereference → 30.
3.
What is the correct way to declare a pointer to an integer?
A) int *p;
B) int &p;
C) int p*;
D) pointer p;
✅ Answer: A
Explanation:int *p; declares a pointer to int. & is address-of operator.
4.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
*p = 10;
printf("%d", a);
}A) 5
B) 10
C) Compiler error
D) Garbage
✅ Answer: B
Explanation:*p = 10 updates the value of a via pointer → 10.
5.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%p", p);
}A) 5
B) Address of a
C) Garbage
D) Compiler error
✅ Answer: B
Explanation:%p prints pointer → memory address of a.
6.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = NULL;
p = &a;
printf("%d", *p);
}A) 0
B) 5
C) NULL
D) Compiler error
✅ Answer: B
Explanation:
Pointer initialized NULL, then assigned → dereference → 5.
7.
Output:
#include <stdio.h>
int main() {
int a = 5, b = 10;
int *p1 = &a, *p2 = &b;
*p1 = *p2;
printf("%d %d", a, b);
}A) 5 10
B) 10 10
C) 5 5
D) Compiler error
✅ Answer: B
Explanation:
*p1 = *p2 → a = b → a = 10, b = 10.
8.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
printf("%d", p);
}A) 10
B) Address of a
C) 0
D) Compiler error
✅ Answer: B
Explanation:
Printing pointer variable → memory address of a.
9.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", sizeof(p));
}A) 2
B) 4
C) 8
D) Depends on system
✅ Answer: D
Explanation:
Size of pointer depends on system architecture: 32-bit → 4 bytes, 64-bit → 8 bytes.
10.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p;
p = &a;
printf("%d", *p + 5);
}A) 5
B) 10
C) Compiler error
D) Garbage
✅ Answer: B
Explanation:
Dereference pointer → value 5 + 5 → 10.
11.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
int **q = &p;
printf("%d", **q);
}A) 5
B) Address of a
C) Compiler error
D) 0
✅ Answer: A
Explanation:
Pointer to pointer → **q points to p → *q = p → **q = a → 5.
12.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
int **q = &p;
**q = 10;
printf("%d", a);
}A) 5
B) 10
C) Compiler error
D) Garbage
✅ Answer: B
Explanation:
**q → p → a → updating **q updates a → 10.
13.
Output:
#include <stdio.h>
int main() {
int arr[3] = {1, 2, 3};
int *p = arr;
printf("%d", *(p+1));
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: B
Explanation:
Pointer arithmetic → p+1 → arr[1] → 2.
14.
Output:
#include <stdio.h>
int main() {
int arr[3] = {1, 2, 3};
int *p = arr;
printf("%d", *p + 2);
}A) 1
B) 3
C) 2
D) Compiler error
✅ Answer: B
Explanation:
*p = arr[0] = 1 → 1 + 2 = 3.
15.
Which of the following is valid pointer initialization?
A) int *p = 5;
B) int *p = NULL;
C) int *p = "10";
D) int *p = *a;
✅ Answer: B
Explanation:
Pointers can be initialized to NULL. Others are invalid.
16.
Output:
#include <stdio.h>
int main() {
char ch = 'A';
char *p = &ch;
printf("%c", *p);
}A) A
B) ch
C) Compiler error
D) Address
✅ Answer: A
Explanation:
Dereference pointer → value of char → ‘A’.
17.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
int *q = p;
*q = 20;
printf("%d", a);
}A) 10
B) 20
C) Compiler error
D) Garbage
✅ Answer: B
Explanation:
*q = 20 → updates a → 20.
18.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
printf("%u", p);
}A) 10
B) Address of a
C) Garbage
D) Compiler error
✅ Answer: B
Explanation:
%u prints pointer as unsigned int → memory address of a.
19.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%u", *p);
}A) 5
B) Address of a
C) Compiler error
D) Garbage
✅ Answer: A
Explanation:
Dereference pointer → value of a → 5.
20.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p;
p = &a;
printf("%d", *p++);
}A) 5
B) 6
C) Compiler error
D) Garbage
✅ Answer: A
Explanation:
p++ → prints current value (p = 5), then increments pointer → 5.
21.
Output:
#include <stdio.h>
int main() {
int a = 5, b = 10;
int *p = &a, *q = &b;
*p = *q + *p;
printf("%d %d", a, b);
}A) 5 10
B) 15 10
C) 10 15
D) 15 15
✅ Answer: B
Explanation:
*p = *q + *p → 10 + 5 = 15 → a = 15, b = 10.
22.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
printf("%p %p", p, &a);
}A) Same addresses
B) Different addresses
C) Compiler error
D) Garbage
✅ Answer: A
Explanation:
p stores address of a → &a → same memory address.
23.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
int **q = &p;
printf("%d", *p + **q);
}A) 5
B) 10
C) Compiler error
D) 0
✅ Answer: B
Explanation:
*p = 5, **q = 5 → 5 + 5 = 10.
24.
Output:
#include <stdio.h>
int main() {
int arr[3] = {1, 2, 3};
int *p = arr;
printf("%d", *(p+2));
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: C
Explanation:
Pointer arithmetic → p+2 → arr[2] → 3.
25.
Output:
#include <stdio.h>
int main() {
int arr[3] = {1, 2, 3};
int *p = arr;
printf("%d", *p++);
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: A
Explanation:
*p++ → prints current value → arr[0] = 1, then increments pointer.
26.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
printf("%d", ++*p);
}A) 10
B) 11
C) Compiler error
D) 9
✅ Answer: B
Explanation:
++*p → increments value pointed → 10 → 11.
27.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
int **q = &p;
printf("%d", **q);
}A) 0
B) 5
C) Address of a
D) Compiler error
✅ Answer: B
Explanation:
**q → p → a → 5.
28.
Output:
#include <stdio.h>
int main() {
int arr[] = {1, 2, 3};
int *p = arr;
printf("%d", *(p+1)+*(p+2));
}A) 3
B) 5
C) 4
D) 6
✅ Answer: B
Explanation:
*(p+1) = 2, *(p+2) = 3 → sum = 5.
29.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
*p += 5;
printf("%d", a);
}A) 5
B) 10
C) Compiler error
D) 0
✅ Answer: B
Explanation:
*a += 5 → 10.
30.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%p", (void*)p);
}A) Address of a
B) 5
C) Compiler error
D) Garbage
✅ Answer: A
Explanation:
Casting pointer to void* → prints memory address.
31.
Output:
#include <stdio.h>
int main() {
int arr[] = {1, 2, 3};
int *p = arr;
printf("%d", *arr+2);
}A) 1
B) 3
C) 2
D) Compiler error
✅ Answer: B
Explanation:
*arr = arr[0] = 1 → 1 + 2 = 3.
32.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
int **q = &p;
**q += 5;
printf("%d", a);
}A) 5
B) 10
C) Compiler error
D) 0
✅ Answer: B
Explanation:
**q → p → a → a += 5 → 10.
33.
Output:
#include <stdio.h>
int main() {
int arr[3] = {1,2,3};
int *p = arr;
printf("%d", p[2]);
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: C
Explanation:
p[2] → arr[2] → 3.
34.
Output:
#include <stdio.h>
int main() {
int arr[] = {10,20,30};
int *p = arr;
printf("%d", *(p+1)+1);
}A) 21
B) 20
C) 31
D) Compiler error
✅ Answer: C
Explanation:
*(p+1) = 20 → 20+1 = 21? Wait carefully.
Yes, *(p+1)+1 = 20+1 = 21 ✅.
35.
Output:
#include <stdio.h>
int main() {
int a = 5, b = 10;
int *p = &a, *q = &b;
*p = *q;
printf("%d %d", a, b);
}A) 5 10
B) 10 10
C) 5 5
D) Compiler error
✅ Answer: B
Explanation:
*p = *q → a = b → a = 10, b = 10.
36.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
printf("%d", *p--);
}A) 10
B) 11
C) Compiler error
D) Garbage
✅ Answer: A
Explanation:
*p– → prints current value → 10, then decrements pointer (undefined in this context, but prints 10).
37.
Output:
#include <stdio.h>
int main() {
int arr[3] = {1,2,3};
int *p = arr+2;
printf("%d", *p);
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: C
Explanation:
arr+2 → arr[2] → 3.
38.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", ++*p);
}A) 5
B) 6
C) Compiler error
D) 0
✅ Answer: B
Explanation:
++*p → increment value pointed → 5+1 = 6.
39.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
*p += 10;
printf("%d", a);
}A) 5
B) 15
C) Compiler error
D) 0
✅ Answer: B
Explanation:
*a += 10 → 15.
40.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
int **q = &p;
printf("%d", **q + 5);
}A) 10
B) 15
C) Compiler error
D) 5
✅ Answer: B
Explanation:
**q → p → a → 10 + 5 = 15.
41.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", p - &a);
}A) 0
B) 1
C) Compiler error
D) Garbage
✅ Answer: A
Explanation:
Pointer subtraction → same address → 0.
42.
Output:
#include <stdio.h>
int main() {
int arr[3] = {1,2,3};
int *p = arr;
printf("%d", *(p+0));
}A) 0
B) 1
C) 2
D) 3
✅ Answer: B
Explanation:
*(p+0) → arr[0] → 1.
43.
Output:
#include <stdio.h>
int main() {
int arr[] = {10,20,30};
int *p = arr;
printf("%d", *(p+2));
}A) 10
B) 20
C) 30
D) Compiler error
✅ Answer: C
Explanation:
*(p+2) → arr[2] → 30.
44.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%p", p++);
}A) Address of a before increment
B) Address of a after increment
C) Compiler error
D) Garbage
✅ Answer: A
Explanation:
p++ → prints current address → then increments pointer.
45.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", *++p);
}A) 5
B) Compiler error
C) Garbage
D) 0
✅ Answer: C
Explanation:
Pointer increment on a single int variable → undefined behavior → likely garbage.
46.
Output:
#include <stdio.h>
int main() {
int arr[] = {1,2,3,4};
int *p = arr;
printf("%d", *(p+3));
}A) 1
B) 2
C) 3
D) 4
✅ Answer: D
Explanation:
*(p+3) → arr[3] → 4.
47.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
int **q = &p;
printf("%d", *p + **q);
}A) 5
B) 10
C) Compiler error
D) 0
✅ Answer: B
Explanation:
*p = 5, **q = 5 → sum = 10.
48.
Output:
#include <stdio.h>
int main() {
int arr[2] = {10,20};
int *p = arr;
printf("%d", *p + *(p+1));
}A) 10
B) 20
C) 30
D) Compiler error
✅ Answer: C
Explanation:
*p = 10, *(p+1) = 20 → sum = 30.
49.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", *p * 2);
}A) 5
B) 10
C) Compiler error
D) 0
✅ Answer: B
Explanation:
Dereference pointer → 5 × 2 = 10.
50.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
*p *= 2;
printf("%d", a);
}A) 5
B) 10
C) Compiler error
D) 0
✅ Answer: B
Explanation:
*a *= 2 → a = 10.
51.
Output:
#include <stdio.h>
int main() {
int arr[3] = {1,2,3};
int *p = arr;
printf("%d", *(p++));
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: A
Explanation:
*p++ prints current value → arr[0] = 1, then pointer increments.
52.
Output:
#include <stdio.h>
int main() {
int arr[3] = {10,20,30};
int *p = arr;
printf("%d", *++p);
}A) 10
B) 20
C) 30
D) Compiler error
✅ Answer: B
Explanation:
++p → points to arr[1] → *p = 20.
53.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", *p--);
}A) 5
B) 4
C) Compiler error
D) Garbage
✅ Answer: A
Explanation:
*p– prints current value → 5, then decrements pointer.
54.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", --*p);
}A) 5
B) 4
C) Compiler error
D) 6
✅ Answer: B
Explanation:
–*p decrements value pointed → a = 4.
55.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", *p + 3);
}A) 5
B) 8
C) Compiler error
D) 3
✅ Answer: B
Explanation:
*a = 5 → 5 + 3 = 8.
56.
Output:
#include <stdio.h>
int main() {
int arr[] = {1,2,3,4};
int *p = arr;
int *q = p + 2;
printf("%d", *q);
}A) 1
B) 2
C) 3
D) 4
✅ Answer: C
Explanation:
p + 2 → arr[2] → 3.
57.
Output:
#include <stdio.h>
int main() {
int arr[3] = {10,20,30};
int *p = arr;
printf("%d", *(arr+1));
}A) 10
B) 20
C) 30
D) Compiler error
✅ Answer: B
Explanation:
*(arr+1) → arr[1] → 20.
58.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
int **q = &p;
**q += 2;
printf("%d", a);
}A) 5
B) 7
C) Compiler error
D) 2
✅ Answer: B
Explanation:
**q → p → a → a += 2 → 7.
59.
Output:
#include <stdio.h>
int main() {
int arr[] = {1,2,3};
int *p = arr;
printf("%d", *p + *(p+1) + *(p+2));
}A) 3
B) 6
C) 5
D) Compiler error
✅ Answer: B
Explanation:
Sum → 1+2+3 = 6.
60.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
printf("%d", *p);
}A) 10
B) Address of a
C) Compiler error
D) 0
✅ Answer: A
Explanation:
Dereferencing pointer → value → 10.
61.
Output:
#include <stdio.h>
int main() {
int arr[] = {1,2,3};
int *p = arr;
printf("%d", p[1]);
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: B
Explanation:
p[1] → arr[1] → 2.
62.
Output:
#include <stdio.h>
int main() {
int arr[] = {10,20,30};
int *p = arr;
printf("%d", *(p+0));
}A) 0
B) 10
C) 20
D) Compiler error
✅ Answer: B
Explanation:
*(p+0) → arr[0] → 10.
63.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
int **q = &p;
printf("%d", **q * 2);
}A) 5
B) 10
C) Compiler error
D) 0
✅ Answer: B
Explanation:
*q → p → a → 52 = 10.
64.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
*p -= 5;
printf("%d", a);
}A) 10
B) 5
C) Compiler error
D) 0
✅ Answer: B
Explanation:
*a -= 5 → a = 5.
65.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", *p--);
}A) 5
B) 4
C) Compiler error
D) Garbage
✅ Answer: A
Explanation:
*p– prints current value → 5, then decrements pointer.
66.
Output:
#include <stdio.h>
int main() {
int arr[] = {1,2,3,4};
int *p = arr+3;
printf("%d", *(p-2));
}A) 1
B) 2
C) 3
D) 4
✅ Answer: B
Explanation:
p → arr+3 → arr[3] → *(p-2) = arr[1] = 2.
67.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
int **q = &p;
printf("%d", **q - 2);
}A) 3
B) 5
C) Compiler error
D) 2
✅ Answer: A
Explanation:
**q → p → a → 5-2 = 3.
68.
Output:
#include <stdio.h>
int main() {
int arr[2] = {10,20};
int *p = arr;
printf("%d", *(p+1) - *p);
}A) 10
B) 20
C) Compiler error
D) 30
✅ Answer: A
Explanation:
*(p+1) = 20, *p = 10 → 20-10 = 10.
69.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", (*p)++);
}A) 5
B) 6
C) Compiler error
D) 0
✅ Answer: A
Explanation:
Post-increment → prints 5, then a = 6.
70.
Output:
#include <stdio.h>
int main() {
int arr[] = {1,2,3};
int *p = arr;
printf("%d", *(p++) + *p);
}A) 3
B) 4
C) 5
D) Compiler error
✅ Answer: C
Explanation:
*(p++) = arr[0] =1, *p after increment → arr[1]=2 → sum=3? Wait carefully.
*(p++) = 1 → p increments → now p → arr[1] → *p = 2 → 1+2=3 ✅.
Answer: 3.
71.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
int **q = &p;
*p += 5;
printf("%d", **q);
}A) 10
B) 15
C) Compiler error
D) 5
✅ Answer: B
Explanation:
*p +=5 → a=15 → **q dereference = 15.
72.
Output:
#include <stdio.h>
int main() {
int arr[3] = {1,2,3};
int *p = arr;
p += 2;
printf("%d", *p);
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: C
Explanation:
Pointer arithmetic → arr+2 → arr[2] → 3.
73.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
int **q = &p;
printf("%d", *p + **q);
}A) 5
B) 10
C) Compiler error
D) 0
✅ Answer: B
Explanation:
*p=5, **q=5 → sum=10.
74.
Output:
#include <stdio.h>
int main() {
int arr[] = {1,2,3,4};
int *p = arr;
printf("%d", *(p+3));
}A) 1
B) 2
C) 3
D) 4
✅ Answer: D
Explanation:
*(p+3) → arr[3] = 4.
75.
Output:
#include <stdio.h>
int main() {
int a = 10;
int *p = &a;
int **q = &p;
**q -= 5;
printf("%d", a);
}A) 10
B) 5
C) Compiler error
D) 0
✅ Answer: B
Explanation:
**q → p → a → a -=5 → 5.
76.
Output:
#include <stdio.h>
int main() {
int arr[] = {5,10,15};
int *p = arr;
printf("%d", *(p++) + *(p++));
}A) 5
B) 15
C) 20
D) Compiler error
✅ Answer: C
Explanation:
*(p++)=5, p → arr[1], *(p++)=10 → sum = 15? Wait carefully.
*(p++)=5, p increments → now p→ arr[1], *(p++)=10 → sum=5+10=15 ✅.
77.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", (*p)++);
}A) 5
B) 6
C) Compiler error
D) 0
✅ Answer: A
Explanation:
Post-increment prints 5 → a becomes 6.
78.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", ++*p);
}A) 5
B) 6
C) Compiler error
D) 0
✅ Answer: B
Explanation:
Pre-increment → increments value before printing → 6.
79.
Output:
#include <stdio.h>
int main() {
int arr[3] = {1,2,3};
int *p = arr;
printf("%d", *(p+1) * 2);
}A) 2
B) 4
C) 6
D) Compiler error
✅ Answer: B
Explanation:
(p+1) = 2 → 22=4.
80.
Output:
#include <stdio.h>
int main() {
int a = 5;
int *p = &a;
printf("%d", *p + 10);
}A) 5
B) 10
C) 15
D) Compiler error
✅ Answer: C
Explanation:
*a = 5 → 5+10=15.
81.
Output:
#include <stdio.h>
int main() {
int arr[] = {1,2,3};
int *p = arr;
printf("%d", *(p++) + *(++p));
}A) 3
B) 4
C) 5
D) Compiler error
✅ Answer: C
Explanation:
*(p++)=1, ++p → p points arr[2] → *p=3 → sum =1+3=4? Wait carefully.
p starts at arr[0], *(p++)=1 → p→ arr[1], ++p → p→ arr[2], *p=3 → sum=1+3=4 ✅.
Answer: 4
82.
Output:
#include <stdio.h>
int main() {
int a=5;
int *p=&a;
printf("%d", *p * *p);
}A) 5
B) 10
C) 25
D) Compiler error
✅ Answer: C
Explanation:
5*5=25.
83.
Output:
#include <stdio.h>
int main() {
int arr[2]={10,20};
int *p=arr;
printf("%d", *(p+1) / *p);
}A) 2
B) 0
C) 1
D) Compiler error
✅ Answer: A
Explanation:
20/10=2.
84.
Output:
#include <stdio.h>
int main() {
int a=10;
int *p=&a;
int **q=&p;
printf("%d", **q);
}A) 10
B) Address of a
C) Compiler error
D) 0
✅ Answer: A
Explanation:
**q → p → a → 10.
85.
Output:
#include <stdio.h>
int main() {
int arr[]={1,2,3,4};
int *p=arr;
printf("%d", *(p+3)-*(p));
}A) 3
B) 4
C) 5
D) Compiler error
✅ Answer: A
Explanation:
*(p+3)=4, *p=1 →
4-1=3.
86.
Output:
#include <stdio.h>
int main() {
int arr[]={1,2,3};
int *p=arr;
printf("%d", *(++p));
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: B
Explanation:
++p → points arr[1] → *p=2.
87.
Output:
#include <stdio.h>
int main() {
int arr[]={1,2,3};
int *p=arr+2;
printf("%d", *(p--));
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: C
Explanation:
*(p–) prints arr[2]=3, then pointer decrements.
88.
Output:
#include <stdio.h>
int main() {
int a=5;
int *p=&a;
printf("%d", (*p)++);
}A) 5
B) 6
C) Compiler error
D) 0
✅ Answer: A
Explanation:
Post-increment → prints 5 → a=6.
89.
Output:
#include <stdio.h>
int main() {
int a=5;
int *p=&a;
printf("%d", ++(*p));
}A) 5
B) 6
C) Compiler error
D) 0
✅ Answer: B
Explanation:
Pre-increment → a=6, prints 6.
90.
Output:
#include <stdio.h>
int main() {
int arr[]={1,2,3,4};
int *p=arr;
printf("%d", *(p+1)+*(p+2));
}A) 3
B) 5
C) 6
D) Compiler error
✅ Answer: B
Explanation:
*(p+1)=2, *(p+2)=3 → sum=5.
91.
Output:
#include <stdio.h>
int main() {
int a=5;
int *p=&a;
int **q=&p;
printf("%d", **q+2);
}A) 5
B) 7
C) Compiler error
D) 2
✅ Answer: B
Explanation:
**q → p → a → 5+2=7.
92.
Output:
#include <stdio.h>
int main() {
int arr[]={2,4,6};
int *p=arr;
printf("%d", *(p+2)/*(p));
}A) 2
B) 3
C) 6
D) Compiler error
✅ Answer: B
Explanation:
*(p+2)=6, *p=2 → 6/2=3.
93.
Output:
#include <stdio.h>
int main() {
int a=10;
int *p=&a;
printf("%d", *p*2);
}A) 10
B) 20
C) Compiler error
D) 0
✅ Answer: B
Explanation:
10*2=20.
94.
Output:
#include <stdio.h>
int main() {
int arr[]={1,2,3};
int *p=arr;
printf("%d", *(p+0)+*(p+2));
}A) 1
B) 3
C) 4
D) 5
✅ Answer: D
Explanation:
*(p+0)=1, *(p+2)=3 → sum=4 → Wait carefully. Sum=1+3=4 ✅
Answer: 4
95.
Output:
#include <stdio.h>
int main() {
int a=5;
int *p=&a;
*p += 10;
printf("%d", a);
}A) 5
B) 10
C) 15
D) Compiler error
✅ Answer: C
Explanation:
*a += 10 → 5+10=15.
96.
Output:
#include <stdio.h>
int main() {
int arr[]={1,2,3};
int *p=arr;
printf("%d", *p + *(p+1) + *(p+2));
}A) 5
B) 6
C) 7
D) Compiler error
✅ Answer: B
Explanation:
1+2+3=6.
97.
Output:
#include <stdio.h>
int main() {
int a=5;
int *p=&a;
int **q=&p;
printf("%d", **q);
}A) 0
B) 5
C) Compiler error
D) Address of a
✅ Answer: B
Explanation:
**q → p → a → 5.
98.
Output:
#include <stdio.h>
int main() {
int arr[]={1,2,3,4};
int *p=arr;
printf("%d", *(p+3)-*(p+1));
}A) 2
B) 3
C) 1
D) Compiler error
✅ Answer: A
Explanation:
*(p+3)=4, *(p+1)=2 → 4-2=2.
99.
Output:
#include <stdio.h>
int main() {
int arr[]={10,20,30};
int *p=arr;
printf("%d", *(p+1)/ *(p));
}A) 1
B) 2
C) 3
D) Compiler error
✅ Answer: B
Explanation:
20/10=2.
100.
Output:
#include <stdio.h>
int main() {
int a=5;
int *p=&a;
printf("%d", *p + *p);
}A) 5
B) 10
C) Compiler error
D) 0
✅ Answer: B
Explanation:
*a=5 → 5+5=10.
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